AP EAMCET · Chemistry · Thermodynamics (C)
At \(298 \mathrm{~K}, \Delta_r \mathrm{G}^{\ominus}\) for the following reaction is \(165.469 \mathrm{~kJ} \mathrm{~mol}^{-1}\).
What is the equilibrium constant for this reaction? \(\left(R=8.3 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}\right)\)
\(\frac{3}{2} \mathrm{O}_2(\mathrm{~g}) \longrightarrow \mathrm{O}_3(\mathrm{~g})\)
- A \(10^{29}\)
- B \(10^{-29}\)
- C \(5 \times 10^{-27}\)
- D \(5 \times 10^{+27}\)
Answer & Solution
Correct Answer
(B) \(10^{-29}\)
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