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AP EAMCET · Chemistry · Chemical Bonding and Molecular Structure

Arrange the following species in the correct order of their stabilities
\(\mathrm{N}_2^{-}, \mathrm{C}_2, \mathrm{Ne}_2, \mathrm{O}_2^{2-}\)

  1. A \(\mathrm{Ne}_2 < \mathrm{O}_2^{2-} < \mathrm{C}_2 < \mathrm{N}_2^{-}\)
  2. B \(\mathrm{Ne}_2 < \mathrm{C}_2 < \mathrm{O}_2^{2-} < \mathrm{N}_2^{-}\)
  3. C \(\mathrm{Ne}_2 < \mathrm{N}_2^{-} < \mathrm{O}_2^{2-} < \mathrm{C}_2\)
  4. D \(\mathrm{Ne}_2 < \mathrm{O}_2^{2-} < \mathrm{N}_2^{-} < \mathrm{C}_2\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\mathrm{Ne}_2 < \mathrm{O}_2^{2-} < \mathrm{C}_2 < \mathrm{N}_2^{-}\)

Step-by-step Solution

Detailed explanation

Higher the bond order, more is the stability. The bond order of the given species can be calculated as (i) \(\mathrm{N}_2^{-}=\)Diatomic molecule Number of electrons \(=(7+7+1)=15 e^{-}\) i.e. B.O. = 2.5 (ii) \(\mathrm{C}_2=\) Diatomic molecule Number of electrons…