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AP EAMCET · Chemistry · Electrochemistry

A solution containing \(4.5 \mathrm{mM}\) of \(\mathrm{MnO}_4^{-}\)and \(15 \mathrm{mM}\) of \(\mathrm{Mn}^{2+}\) shows \(\mathrm{pH}\) of 2 . The potential of half-cell reaction is ...... .
(Given, \(\log 15=1.76\) and \(\log 45=1.653\) and standard potential of \(\mathrm{MnO}_4^{-} \longrightarrow \mathrm{Mn}^{2+}\) ) is \(1.51 \mathrm{~V}\) )

  1. A \(1.51 \mathrm{~V}\)
  2. B \(1.31 \mathrm{~V}\)
  3. C \(1.71 \mathrm{~V}\)
  4. D \(1.04 \mathrm{~V}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(1.31 \mathrm{~V}\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & \text { (b) } \mathrm{MnO}_4^{-}+8 \mathrm{H}^{+}+5 e^{-} \longrightarrow \mathrm{Mn}^{2+}+4 \mathrm{H}_2 \mathrm{O} \\ & E=E_{\mathrm{Mn}^{\circ}}{ }^{7+} \mathrm{Mn}^{2+} /+\frac{0.059}{5} \log…