AP EAMCET · Maths · Circle
If the point of intersection of the pair of the transverse common tangents and that of the pair of direct common tangents drawn to the circles \(x^2+y^2-14 x+6 y+33=0\) and \(x^2+y^2+30 x-2 y+1=0\) are \(T\) and \(D\) respectively, then the centre of the circle having TD as diameter is
- A \(\left(\frac{39}{2}, \frac{-7}{4}\right)\)
- B \(\left(\frac{39}{4}, \frac{7}{2}\right)\)
- C \(\left(\frac{39}{4}, \frac{-7}{2}\right)\)
- D \(\left(\frac{39}{2}, \frac{-7}{2}\right)\)
Answer & Solution
Correct Answer
(C) \(\left(\frac{39}{4}, \frac{-7}{2}\right)\)
Step-by-step Solution
Detailed explanation
Given, \(C_1: x^2+y^2+30 x-2 y+1=0\)…
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