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NEET · Physics · STD 12 - 5. Magnetism and matter

यदि, एक दूसरे से लम्बवत्, दो ऊधर्वाधर समतलों में प्रेक्षित आभासी नमन (नति) कोण \(\theta_{1}\) तथा \(\theta_{2}\) हैं तो, वास्तविक नमन कोण \(\theta\) का मान किस समीकरण से प्राप्त होगा?

  1. A \(\cot ^2 \theta=\cot ^2 \theta_1+\cot ^2 \theta_2\)
  2. B \(\tan ^2 \theta=\tan ^2 \theta_1+\tan ^2 \theta_2\)
  3. C \(\cot ^2 \theta=\cot ^2 \theta_1-\cot ^2 \theta_2\)
  4. D \(\tan ^2 \theta=\tan ^2 \theta_1-\tan ^2 \theta_2\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\cot ^2 \theta=\cot ^2 \theta_1+\cot ^2 \theta_2\)

Step-by-step Solution

Detailed explanation

Let \(B_H\) and \(B_v\) be the horizontal and vertical components of earth's magnetic field \(\vec B\). Since \(\theta\) is the angle of dip \(\tan \theta = \frac{B_V}{B_H}\)
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