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NEET · Chemistry · STD 11 - 1. Some basic concept of chemistry

निम्नलिखित अभिक्रिया के अनुसार \(0.5 \,M\, HCl\) विलयन के \(50\, mL\) को उदासीन करने के लिए \(95\, \%\) शुद्ध \(CaCO _{3}\) के कितने द्रव्यमान की आवश्यकता होगी ? \(CaCO _{3( s )}+2 HCl _{( aq )} \rightarrow CaCl _{2( aq )}+ CO _{2( g )}+2 H _{2} O _{( l )}\) [दशमलव बिंदु के दूसरे स्थान तक परिकलित कीजिए]

  1. A \(1.32\)
  2. B \(3.65\)
  3. C \(9.50\)
  4. D \(1.25\)
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Answer & Solution

Correct Answer

(A) \(1.32\)

Step-by-step Solution

Detailed explanation

\(CaCO _{3(s)}+2 HCl _{(\text {aq) })} \rightarrow CaCl _{2(a q)}+ CO _{2(q)}+ H _{2} O _{(q)}\) no. of moles of \(CaCO _{3}\) (pure) \(=\frac{1}{2} \times\) mole of \(HCl\)
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