किसी पारिस्थितिक तंत्र (ईकोसिस्टम) में यदि पृथम पोषी स्तर का नेट प्राथमिक उत्पादन (\(NPP\)) \(100 x\left(\mathrm{kcal} \mathrm{m}^{-2}\right)\) प्रतिवर्ष है। तब उसी पारिस्थितिक तंत्र के तृतीय पोषी स्तर का \(GPP\) (सकल प्राथमिक उत्पादन) क्या होगा ?

A \(x\left(\mathrm{kcal} \mathrm{m}^{-2}\right) \mathrm{yr}^{-1}\) प्रतिवर्ष
B \(10 x\left(\mathrm{kcal} \mathrm{m}^{-2}\right) \mathrm{yr}^{-1}\) प्रतिवर्ष
C \(\frac{100 x}{3 x}\left(\mathrm{kcal} \mathrm{m}^{-2}\right) \mathrm{yr}^{-1}\) प्रतिवर्ष
D \(\frac{x}{10}\left(\mathrm{kcal} \mathrm{m}^{-2}\right) \mathrm{yr}^{-1}\) प्रतिवर्ष

Verified Solution

Answer & Solution

Correct Answer

(B) \(10 x\left(\mathrm{kcal} \mathrm{m}^{-2}\right) \mathrm{yr}^{-1}\) प्रतिवर्ष

Step-by-step Solution

Detailed explanation

\(NPP\) at first trophic level would be the \(GPP\) for second trophic level. \(NPP\) at second trophic level would be \(GPP\) for third trophic level. Therefore, \(100 x\left(\mathrm{kcal} / \mathrm{m}^2 / \mathrm{yr}\right)\) would be \(GPP\) at second trophic level and \(100 x\) \(\times 10 \%\left(\mathrm{kcal} / \mathrm{m}^2 / \mathrm{yr}\right)\) i.e., \(10 \times\left(\mathrm{kcal} / \mathrm{m}^2 / \mathrm{yr}\right)\) energy would be \(GPP\) at third trophic level.

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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