એક પર્યાપ્ત ઉંચાઇના મકાનની છત પરથી એક લોલક લટકાવેલ છે, જે સાદા આવર્ત દોલકની જેમ મુક્તતાથી આગળ-પાછળ ગતિ કરી શકે છે. તેના સમતોલન સ્થાનથી \(5\;m\) અંતરે આ લોલકનો પ્રવેગ \(20\; m/s^2 \) છે. આ દોલનનો આવર્તકાળ કેટલો થાય?

A \(2\pi\;s\)
B \(\pi \;s\)
C \(1\;s\)
D \(2\;s\)

Verified Solution

Answer & Solution

Correct Answer

(B) \(\pi \;s\)

Step-by-step Solution

Detailed explanation

Magnitude of acceleration of a particle moving in a \(SHM\) is, \(|a|=\omega^{2} y ;\) where \(y\) is amplitude. \(\Rightarrow \quad 20=\omega^{2}(5) \Rightarrow \omega=2 \mathrm{rad} \mathrm{s}^{-1}\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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