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NEET · Physics · STD 12 -7. Alternating current

આકૃતિમાં દર્શાવેલ પરિપથનો ચોખ્ખો ઈમ્પિડન્સ \(........\,\Omega\) હશે.

  1. A \(15\)
  2. B \(10 \sqrt{2}\)
  3. C \(25\)
  4. D \(5 \sqrt{5}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(5 \sqrt{5}\)

Step-by-step Solution

Detailed explanation

\(X_L =\frac{50}{ L } \times 10^{-3} \times 2 \pi \times 50=5\,\Omega\) \(X_C =\frac{1}{2 \pi \times 50 \times \frac{10^3}{\pi} \times 10^{-6}}=10\,\Omega\)
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