\(15\; cm\) કેન્દ્રલંબાઇના એક અંતર્ગોળ અરીસાથી \(40\;cm\) પર એક વસ્તુ મુકેલ છે. જો આ વસ્તુને \(20\;cm\) આ અરીસા તરફ ખસેડવામાં આવે, તો પ્રતિબિંબનું સ્થાનાંતર કેટલું હશે?

A અરીસાથી \(30 \;cm\) દૂર
B અરીસાથી \(36\; cm\) દૂર
C \(36\; cm\) અરીસા તરફ
D \(36\; cm\) અરીસા તરફ

Verified Solution

Answer & Solution

Correct Answer

(B) અરીસાથી \(36\; cm\) દૂર

Step-by-step Solution

Detailed explanation

Using mirror formula, \(\frac{1}{f}=\frac{1}{v_{1}}+\frac{1}{u_{1}} ;-\frac{1}{15}=\frac{1}{v_{1}}-\frac{1}{40} \Rightarrow \frac{1}{v_{1}}=\frac{1}{-15}+\frac{1}{40}\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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