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JEE Mains · Chemistry · STD 12 - 8.2 Carboxylic acids and their derivative

પ્રક્રિયાઓના નીચેના ક્રમમાં એક સંયોજન \(A\), (પરમાણુ સૂત્ર \(\left.{C}_{6} {H}_{12} {O}_{2}\right)\) સાથે સીધી સાંકળ શૃંખલા \(C_{4}\) કાર્બોક્સિલિક એસિડ આપે છે.  \(A\) શું છે: \(A \frac{{Li} {A} {H} {H}_{4}}{{H}_{3} {O}^{+}} \longrightarrow B \stackrel{\text { Oxidation }}{\longrightarrow} {C}_{4}-\) કાર્બોક્સિલિક એસિડ

  1. A \({CH}_{3}-{CH}_{2}-{COO}-{CH}_{2}-{CH}_{2}-{CH}_{3}\)
  2. B \(\begin{array}{*{20}{c}} {OH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\ {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\ {{\rm{C}}{{\rm{H}}_3} - {\rm{C}}{{\rm{H}}_2} - {\rm{CH}} - {\rm{C}}{{\rm{H}}_2} - {\rm{O}} - {\rm{CH}} = {\rm{C}}{{\rm{H}}_2}} \end{array}\)
  3. C \({CH}_{3}-{CH}_{2}-{CH}_{2}-{COO}-{CH}_{2}-{CH}_{3}\)
  4. D \({CH}_{3}-{CH}_{2}-{CH}_{2}-{O}-{CH}={CH}-{CH}_{2}-{OH}\)
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(C) \({CH}_{3}-{CH}_{2}-{CH}_{2}-{COO}-{CH}_{2}-{CH}_{3}\)

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