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JEE Mains · Chemistry · STD 11 - 9. Hydricarbon

નીચેની પ્રક્રિયામાં મુખ્ય નીપજ (\(Y\)) શું હશે ?  \(\begin{array}{*{20}{c}}
  {C{H_3}\,\,\,\,\,\,\,\,\,} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_3} - CH - C = CH} 
\end{array}\xrightarrow[{{H_2}O}]{{HgS{O_4},{H_2}S{O_4}}}X\) \(\xrightarrow[{(ii)\,conc.{H_2}S{O_4}/\Delta }]{{(i)\,{C_2}{H_5}MgBr,{H_2}O}}Y\)

  1. A \(\begin{array}{*{20}{c}}   {C{H_3}\,\,\,\,\,\,\,\,\,\,\,} \\    {||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\    {C{H_3} - C - CH - C{H_3}} \\    {\,\,\,\,\,|} \\    {\,\,\,\,\,\,\,\,\,\,\,\,{C_2}{H_5}}  \end{array}\)
  2. B \(\begin{array}{*{20}{c}}   {C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\    {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\    {C{H_3} - CH - C = CH - C{H_3}} \\    | \\    {\,\,\,\,\,\,C{H_3}}  \end{array}\)
  3. C \(\begin{array}{*{20}{c}}   {C{H_3}\,\,\,\,\,\,\,\,} \\    {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\    {C{H_3} - C = C - C{H_3}} \\    {\,\,\,\,\,\,\,\,\,\,\,\,|} \\    {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_2}C{H_3}}  \end{array}\)
  4. D \(\begin{array}{*{20}{c}}   {C{H_3}\,\,\,\,\,\,\,\,} \\    {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\    {C{H_3} - CH - C = C{H_2}} \\    {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\    {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_2}C{H_3}}  \end{array}\)
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Correct Answer

(C) \(\begin{array}{*{20}{c}}   {C{H_3}\,\,\,\,\,\,\,\,} \\    {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\    {C{H_3} - C = C - C{H_3}} \\    {\,\,\,\,\,\,\,\,\,\,\,\,|} \\    {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_2}C{H_3}}  \end{array}\)

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