WBJEE · Maths · Hyperbola
The eccentricity of the hyperbola \(4 x^2-9 y^2=36\) is
- A \(\frac{\sqrt{11}}{3}\)
- B \(\frac{\sqrt{15}}{3}\)
- C \(\frac{\sqrt{13}}{3}\)
- D \(\frac{\sqrt{14}}{3}\)
Answer & Solution
Correct Answer
(C) \(\frac{\sqrt{13}}{3}\)
Step-by-step Solution
Detailed explanation
Hints: \(\frac{x^2}{9}-\frac{y^2}{4}=1\) \(\begin{aligned} & a=3, b=2 \\ & \therefore e=\sqrt{\frac{a^2+b^2}{a^2}}=\sqrt{\frac{13}{9}}=\frac{\sqrt{13}}{3} \end{aligned}\)
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