WBJEE · Maths · Limits
Let \(f: \mathbb{R} \rightarrow \mathbb{R}\) be a differentiable function and \(f(1)=4\). Then the value of \(\lim _{x \rightarrow 1} \int_4^{f(x)} \frac{2 t}{x-1} d t\), if \(f^{\prime}(1)=2\) is
- A 16
- B 8
- C 4
- D 2
Answer & Solution
Correct Answer
(A) 16
Step-by-step Solution
Detailed explanation
Hint : \(\operatorname{Lim}_{x \rightarrow 1} \int_4^{f(x)} \frac{2 t}{x-1} d t,=\operatorname{Lim}_{x \rightarrow 1}\left[\frac{t^2}{x-1}\right]_4^{f(x)}\)…
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