WBJEE · Maths · Limits
If \(\alpha, \beta\) are the roots of the equation \(a x^2+b x+c=0\) then \(\lim _{x \rightarrow \beta} \frac{1-\cos \left(a x^2+b x+c\right)}{(x-\beta)^2}\) is
- A \((\alpha-\beta)^2\)
- B \(\frac{1}{2}(\alpha-\beta)^2\)
- C \(\frac{a^2}{4}(\alpha-\beta)^2\)
- D \(\frac{a^2}{2}(\alpha-\beta)^2\)
Answer & Solution
Correct Answer
(D) \(\frac{a^2}{2}(\alpha-\beta)^2\)
Step-by-step Solution
Detailed explanation
Hint: \(a x^2+b x+c=a(x-\alpha)(x-\beta)\)…
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