WBJEE · Chemistry · Chemical Kinetics

For a chemical reaction at \(27^{\circ} \mathrm{C},\) the activation energy is \(600 \mathrm{R}\). The ratio of the rate constants at \(327^{\circ} \mathrm{C}\) to that of at \(27^{\circ} \mathrm{C}\)
will be

A 2
B 40
C \(e\)
D \(e^{2}\)

Verified Solution

Answer & Solution

Correct Answer

(C) \(e\)

Step-by-step Solution

Detailed explanation

From Arrhenius equation \[ \begin{array}{l} \operatorname{In} \frac{k_{2}}{k_{1}}=\frac{E_{a}}{R}\left[\frac{1}{T_{1}}-\frac{1}{T_{2}}\right] \\ \operatorname{In} \frac{k_{2}}{k_{1}}=\frac{600 \mathrm{R}}{R}\left(\frac{1}{300}-\frac{1}{600}\right) \end{array} \] or…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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For a chemical reaction at \(27^{\circ} \mathrm{C},\) the activation energy is \(600 \mathrm{R}\). The ratio of the rate constants at \(327^{\circ} \mathrm{C}\) to that of at \(27^{\circ} \mathrm{C}\) will be

Step-by-step Solution

For a chemical reaction at \(27^{\circ} \mathrm{C},\) the activation energy is \(600 \mathrm{R}\). The ratio of the rate constants at \(327^{\circ} \mathrm{C}\) to that of at \(27^{\circ} \mathrm{C}\)
will be