WBJEE · Chemistry · Structure of Atom
As per de-Broglie's formula a macroscopic particle of mass \(100 \mathrm{g}\) and moving at a velocity of \(100 \mathrm{cm} \mathrm{s}^{-1}\) will have a wavelength of
- A \(6.6 \times 10^{-29} \mathrm{cm}\)
- B \(6.6 \times 10^{-30} \mathrm{cm}\)
- C \(6.6 \times 10^{-31} \mathrm{cm}\)
- D \(6.6 \times 10^{-32} \mathrm{cm}\)
Answer & Solution
Correct Answer
(C) \(6.6 \times 10^{-31} \mathrm{cm}\)
Step-by-step Solution
Detailed explanation
According to de-Broglie. wavelength, \(\lambda=\frac{h}{m v}\) Given, \(\quad m=100 \mathrm{g}, v=100 \mathrm{cm} \mathrm{s}^{-1}\) and \[ \begin{aligned} h &=6.6 \times 10^{-34} \mathrm{J}-\mathrm{s} \\ &=6.6 \times 10^{-27} \mathrm{erg}-\mathrm{s} \end{aligned} \] On…
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