TS EAMCET · Maths · Indefinite Integration
\(\int \frac{\tan x}{\sec ^2 x\left(1+\sec ^6 x\right)^{\frac{2}{3}}} d x=\)
- A \(\frac{-1}{2}\left(1+\sec ^6 x\right)^{\frac{1}{3}}+\mathrm{c}\)
- B \(2\left(1+\sec ^6 x\right)^{\frac{4}{3}}+c\)
- C \(\frac{-1}{2}\left(1+\cos ^6 x\right)^{\frac{1}{3}}+c\)
- D \(2\left(1+\cos ^6 x\right)^{\frac{1}{3}}+\mathrm{c}\)
Answer & Solution
Correct Answer
(C) \(\frac{-1}{2}\left(1+\cos ^6 x\right)^{\frac{1}{3}}+c\)
Step-by-step Solution
Detailed explanation
\(\int \frac{\tan x}{\sec ^2 x\left(1+\sec ^6 x\right)^{2 / 3}} d x\) \(=\int \frac{\tan x}{\sec ^6 x\left(\frac{1}{\sec ^6 x}+1\right)^{2 / 3}} d x\) \(=\int \frac{\tan x}{\sec ^6 x\left(\cos ^6 x+1\right)^{2 / 3}} d x\) Let \(1+\cos ^6 x=t\)…
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