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TS EAMCET · Maths · Indefinite Integration

\(\int \frac{\left(x+\sqrt{1+x^2}\right)^2}{\sqrt{1+x^2}} d x=\)

  1. A \(\frac{x}{\sqrt{1+x^2}}+C\)
  2. B \(\log \left|x+\sqrt{1+x^2}\right|+C\)
  3. C \(x+\sqrt{1+x^2}+C\)
  4. D \(\frac{\left(x+\sqrt{1+x^2}\right)^2}{2}+C\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{\left(x+\sqrt{1+x^2}\right)^2}{2}+C\)

Step-by-step Solution

Detailed explanation

Let \(I=\int \frac{\left(x+\sqrt{1+x^2}\right)^2}{\sqrt{1+x^2}} d x\)…