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TS EAMCET · Maths · Limits

\(\lim _{x \rightarrow 0} \frac{3^{\sin x}-2^{\tan x}}{\sin x}=\)

  1. A 0
  2. B 1
  3. C \(\log e 6\)
  4. D \(\log _e \frac{3}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\log _e \frac{3}{2}\)

Step-by-step Solution

Detailed explanation

\(\lim _{x \rightarrow 0} \frac{3^{\sin x}-2^{\tan x}}{\sin x}\) \(=\lim _{x \rightarrow 0} \frac{3^{\sin x}-1-\left(2^{\tan x}-1\right)}{\sin x}=\ln 3-\ln 2=\ln \left(\frac{3}{2}\right)\)