TS EAMCET · Maths · Probability
There are four machines and it is known that exactly two of them are faulty. They are tested one by one, in a random order till both the faulty machines are identified. Then, the probability that only two tests are need is
- A \(\frac{1}{3}\)
- B \(\frac{1}{6}\)
- C \(\frac{1}{2}\)
- D \(\frac{1}{4}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{3}\)
Step-by-step Solution
Detailed explanation
\(\therefore\) Required probability \(=P(\ln\) first two test either both are faulty or both are not faulty) \(=P\) (First two are faulty) \(+P\) (First two are not faulty)…
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