TS EAMCET · Maths · Determinants
The system of equations \(3 x+2 y+z=6\), \(3 x+4 y+3 z=14\) and \(6 x+10 y+8 z=a\), has infinite number of solutions, if \(a\) is equal to
- A \(8\)
- B \(12\)
- C \(24\)
- D \(36\)
Answer & Solution
Correct Answer
(D) \(36\)
Step-by-step Solution
Detailed explanation
Given system of equation is \[ \begin{gathered} 3 x+2 y+z=6 \\ 3 x+4 y+3 z=14 \\ 6 x+10 y+8 z=a \\ A=\left[\begin{array}{rrr} 3 & 2 & 1 \\ 3 & 4 & 3 \\ 6 & 10 & 8 \end{array}\right], B=\left[\begin{array}{r} 6 \\ 14 \\ a \end{array}\right] \end{gathered} \] Here,…
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