TS EAMCET · Maths · Circle
The equation of the incircle of the triangle formed by the lines \(x=0, y=0\) and \(3 x+4 y-24=0\) is
- A \(x^2+y^2-24 x-24 y+144=0\)
- B \(x^2+y^2-6 x-6 y+9=0\)
- C \(x^2+y^2-4 x-4 y+4=0\)
- D \(x^2+y^2-8 x-8 y+16=0\)
Answer & Solution
Correct Answer
(C) \(x^2+y^2-4 x-4 y+4=0\)
Step-by-step Solution
Detailed explanation
Given lines are \(x=0, y=0\) and \(3 x+4 y-24=0\). Let the incircle touches at the radius \(\mathrm{k}\). Equation of circle is given by, \[ (x-h)^2+(y-h)^2=h^2 \] According to question,…
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