TS EAMCET · Maths · Circle
The equation of the direct common tangent of the circles \(x^2+y^2-6 x-4 y-23=0\) and \(x^2+y^2+2 x+2 y+1=0\) is
- A \(6 x-4 y+1=0\)
- B \(3 x-4 y+6=0\)
- C \(4 x+3 y+12=0\)
- D \(2 x-4 y+3=0\)
Answer & Solution
Correct Answer
(C) \(4 x+3 y+12=0\)
Step-by-step Solution
Detailed explanation
Given equations of circles \(x^2+y^2-6 x-4 y-23=\) 0 and \(x^2+y^2+2 x+2 y+1=0\) Equation of common tangent is given by \(\mathrm{S}_1-\mathrm{S}_2=0\).…
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