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TS EAMCET · Maths · Binomial Theorem

The absolute value of the numerically greatest term in the expansion of \((2 x-3 y)^{12}\) when \(x=3\), \(y=2\) is

  1. A \({ }^{12} \mathrm{C}_5 6^{12}\)
  2. B \({ }^{12} \mathrm{C}_6 6^{42}\)
  3. C \({ }^{12} \mathrm{C}_4 6^{12}\)
  4. D \({ }^{12} \mathrm{C}_9 6^{12}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \({ }^{12} \mathrm{C}_6 6^{42}\)

Step-by-step Solution

Detailed explanation

The absolute value of greatest term in \((2 x-3 y)^{12}\) is middle term, so \[ \begin{gathered} T_{\left(\frac{12}{2}\right)}=T_6 \\ \Rightarrow{ }^{12} C_6 \cdot(2 x){ }^6(3 y)^6={ }^{12} C_6 \cdot(2 \cdot 3)^6 \cdot(3 \cdot 2)^6={ }^{12} C_6 \cdot(6)^{12} \end{gathered} \]