TS EAMCET · Maths · Probability
Let \(B(\alpha, \beta, \gamma)\) represents that a bag \(B\) contains \(\alpha\) red balls, \(\beta\) green balls and \(\gamma\) blue balls. Given \(B_1(2,3,2), B_2(3,2,2), B_3(2,2,3)\). A die is rolled. If the die shows up 2 or 3 or 5 , then a ball will be drawn at random from bag \(B_1\). If the die shows up 4 or 6 , then a ball will be drawn at random from bag \(B_2\). If the die shows up 1, then from bag \(B_3\) a ball will be drawn at random. Then the probability of drawing a green ball from a bag thus chosen is
- A \(\frac{2}{7}\)
- B \(\frac{5}{14}\)
- C \(\frac{3}{5}\)
- D \(\frac{2}{3}\)
Answer & Solution
Correct Answer
(B) \(\frac{5}{14}\)
Step-by-step Solution
Detailed explanation
\(P\left(\beta_1\right)=\frac{3}{6}, P\left(\beta_2\right)=\frac{2}{6}, P\left(\beta_3\right)=\frac{1}{6}\) \(P\left(\frac{\beta}{\beta_1}\right)=\frac{3}{7}, P\left(\frac{\beta}{\beta_2}\right)=\frac{2}{7}, P\left(\frac{\beta}{\beta_3}\right)=\frac{2}{7}\) Required probability…
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