TS EAMCET · Maths · Straight Lines
Let \(A(1,1)\) be a point. \(B\) is the image of \(A\) with respect to the line \(x+2 y+2=0\). If \(C\) is the foot of the perpendicular from \(B\) on the line \(3 x+4 y-10=0\), then \(A C\) is equal to
- A \(\frac{1}{\sqrt{2}}\)
- B 3
- C \(\sqrt{3}\)
- D 1
Answer & Solution
Correct Answer
(D) 1
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \text { For } B, \frac{x-1}{1}=\frac{y-1}{2}=\frac{-2(5)}{5} \\ & \Rightarrow x-1=-2 \quad \Rightarrow y-1=-4 \\ & \Rightarrow \quad x=-1 \quad \Rightarrow \quad y=-3 \\ & \therefore \quad B \equiv(-1,-3)\end{aligned}\)…
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