TS EAMCET · Maths · Properties of Triangles
In \(\triangle A B C, A D\) and \(B E\) are medians drawn from \(A\) and \(B\). If \(A D=\frac{7}{2}, \angle D A B=\frac{\pi}{8}\) and \(\angle A B E=\frac{\pi}{4}\), then the area (in sq. units) of \(\triangle A B C\) is
- A \(\frac{7}{12}\)
- B \(\frac{49}{36}\)
- C \(\frac{49}{12}\)
- D \(\frac{7}{36}\)
Answer & Solution
Correct Answer
(A) \(\frac{7}{12}\)
Step-by-step Solution
Detailed explanation
In \(\triangle A B C, A D\) and \(B E\) are medians of \(\triangle A B C\) \(\begin{aligned} A D & =\frac{7}{2} \Rightarrow \angle D A B=\frac{\pi}{8} \\ \angle A B E & =\frac{\pi}{4} \Rightarrow A O=\frac{2}{3} A D=\frac{2}{3} \times \frac{7}{2}=\frac{7}{3} \end{aligned}\)…
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