TS EAMCET · Maths · Complex Number
If \(z=x+i y\) is a complex number and \(|1+i z|=|1-i z|\), then
- A \(\operatorname{Re}(z)>0\)
- B \(|z|=1\)
- C \(z=\bar{Z}\)
- D \(z=-\bar{z}\)
Answer & Solution
Correct Answer
(C) \(z=\bar{Z}\)
Step-by-step Solution
Detailed explanation
We have, \[ \begin{aligned} |1+i z| & =|1-i z| \\ \Rightarrow \quad|1+i(x+i y)| & =|1-i(x+i y)| \\ \Rightarrow \quad|(1-y)+i x| & =|(1+y)-i x| \\ \Rightarrow \quad \sqrt{(1-y)^2+x^2} & =\sqrt{(1+y)^2+x^2} \\ \Rightarrow \quad(1-y)^2+x^2 & =(1+y)^2+x^2 \end{aligned} \]…
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