TS EAMCET · Maths · Differentiation
If \(y=a e^x+b e^{-x}+c\), where \(a, b, c\) are parameters, then \(y^{\prime \prime \prime}\) is equal to
- A \(0\)
- B \(y\)
- C \(y^{\prime}\)
- D \(y^{\prime \prime}\)
Answer & Solution
Correct Answer
(C) \(y^{\prime}\)
Step-by-step Solution
Detailed explanation
We have, \[ \begin{aligned} y & =a e^x+b e^{-x}+c \\ y^{\prime} & =a e^x-b e^{-x} \\ y^{\prime \prime} & =a e^x+b e^{-x} \\ y^{\prime \prime \prime} & =a e^x-b e^{-x}=y^{\prime} \end{aligned} \]
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