TS EAMCET · Maths · Indefinite Integration
If \(\frac{x^2}{2 x^4+7 x^2+6}=\frac{A x+B}{x^2+a}+\frac{C x+D}{a x^2+3}\), then \(A+B+C-2 D\)
- A \(2 a\)
- B \(-2 a\)
- C \(-4 a\)
- D \(4 a\)
Answer & Solution
Correct Answer
(D) \(4 a\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \frac{x^2}{2 x^4+7 x^2+6}=\frac{x^2}{\left(x^2+2\right)\left(2 x^2+3\right)} \\ = & \frac{x^2+2-2}{\left(x^2+2\right)\left(2 x^2+3\right)}=\frac{1}{2 x^2+3}-\frac{2}{\left(x^2+2\right)\left(2 x^2+3\right)}\end{aligned}\)…
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