TS EAMCET · Maths · Binomial Theorem
If \(n C r=C r\) and \(2 \frac{C_1}{C_0}+4 \frac{C_2}{C_1}+6 \frac{C_3}{C_2}+\ldots+2 n \frac{C_n}{C_{n-1}}=650\), then \(n C_2=\)
- A 25
- B 300
- C 225
- D 625
Answer & Solution
Correct Answer
(B) 300
Step-by-step Solution
Detailed explanation
\(T_r=\frac{2 r \cdot{ }^n C_r}{{ }^n C_{r-1}}=\frac{(n-r+1)}{r} \times 2 r=2(n-r+1)\)…
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