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TS EAMCET · Maths · Complex Number

If \(i^{\prime} i^{\prime}\) is the root of the equation \(\mathrm{x}^2+1=0\) then \((1+\sqrt{3} i)^{2023}+(1-\sqrt{3} i)^{2023}=\)

  1. A \(2^{2022}\)
  2. B \(2^{2023}\)
  3. C \(2^{2022}(\sqrt{3})\)
  4. D \(2^{2023}(\sqrt{3})\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(2^{2023}\)

Step-by-step Solution

Detailed explanation

\(\Rightarrow(1+\sqrt{3} i)^{2023}+(1-\sqrt{3} i)^{2023}\)…