TS EAMCET · Maths · Limits
If \(f(x)=\left\{\begin{array}{lll}x-5, & \text { for } x \leq 1 \ 4 x^2-9, & \text { for } 1 < x < 2 \ 3 x+4, & \text { for } x \geq 2,\end{array}\right.\) then \(f^{\prime}\left(2^{+}\right)\)is equal to
- A \(0\)
- B \(2\)
- C \(3\)
- D \(4\)
Answer & Solution
Correct Answer
(C) \(3\)
Step-by-step Solution
Detailed explanation
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