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TS EAMCET · Maths · Continuity and Differentiability

If \(f(x)=\left\{\begin{array}{cc}\frac{\sqrt{1+a x}-\sqrt{1-a x}}{x}, & -1 \leq x < 0 \ \frac{x^2+2}{x-2}, & 0 \leq x \leq 1\end{array}\right.\) is continuous on \([-1,1]\), then \(a=\)

  1. A -1
  2. B -2
  3. C 1
  4. D 2
Verified Solution

Answer & Solution

Correct Answer

(A) -1

Step-by-step Solution

Detailed explanation

We have, \[ f(x)=\left\{\begin{array}{cc} \frac{\sqrt{1+a x}-\sqrt{1-a x}}{x}, & -1 \leq x < 0 \\ \frac{x^2+2}{x-2}, & 0 \leq x \leq 1 \end{array}\right. \] Since, \(f(x)\) is continuous on \([-1,1]\).…