TS EAMCET · Maths · Continuity and Differentiability
If \(f(x)=\left\{\begin{array}{cc}\frac{\sqrt{1+a x}-\sqrt{1-a x}}{x}, & -1 \leq x < 0 \ \frac{x^2+2}{x-2}, & 0 \leq x \leq 1\end{array}\right.\) is continuous on \([-1,1]\), then \(a=\)
- A -1
- B -2
- C 1
- D 2
Answer & Solution
Correct Answer
(A) -1
Step-by-step Solution
Detailed explanation
We have, \[ f(x)=\left\{\begin{array}{cc} \frac{\sqrt{1+a x}-\sqrt{1-a x}}{x}, & -1 \leq x < 0 \\ \frac{x^2+2}{x-2}, & 0 \leq x \leq 1 \end{array}\right. \] Since, \(f(x)\) is continuous on \([-1,1]\).…
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