TS EAMCET · Maths · Differentiation
If \(f(x)=\sqrt{a x}+\frac{a^2}{\sqrt{a x}}\), then \(f^{\prime}(a)\) is equal to
- A \(0\)
- B \(-1\)
- C \(1\)
- D \(a\)
Answer & Solution
Correct Answer
(A) \(0\)
Step-by-step Solution
Detailed explanation
We have, \[ f(x)=\sqrt{a x}+\frac{a^2}{\sqrt{a x}} \] On differentiating w.r.t. \(x\), we get,…
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