TS EAMCET · Maths · Three Dimensional Geometry
If \(D(2,1,0), E(2,0,0)\) and \(F(0,1,0)\) are mid-points of the sides \(B C, C A\) and \(A B\) of \(\triangle A B C\), respectively. Then, the centroid of \(\triangle A B C\) is
- A \(\left(\frac{1}{3}, \frac{1}{3}, \frac{1}{3}\right)\)
- B \(\left(\frac{4}{3}, \frac{2}{3}, 0\right)\)
- C \(\left(-\frac{1}{3}, \frac{1}{3}, \frac{1}{3}\right)\)
- D \(\left(\frac{2}{3}, \frac{1}{3}, \frac{1}{3}\right)\)
Answer & Solution
Correct Answer
(B) \(\left(\frac{4}{3}, \frac{2}{3}, 0\right)\)
Step-by-step Solution
Detailed explanation
Let \(\quad A \equiv\left(x_1, y_1, z_1\right), \quad B \equiv\left(x_2, y_2, z_2\right) \quad\) and \(C \equiv\left(x_3, y_3, z_3\right)\) Since, \(F\) is the mid-point of \(A B\).…
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