TS EAMCET · Maths · Trigonometric Ratios & Identities
If \(\sin \mathrm{A}=-\frac{24}{25}, \cos \mathrm{~B}=\frac{15}{17}, \mathrm{~A}\) does not belong to \(4^{\text {th }}\) quadrant and B does not belong to \(1^{\text {st }}\) quadrant then \((\mathrm{A}+\mathrm{B})\) lies in the quadrant
- A \(1^{\text {st }}\) quadrant
- B \(2^{\text {nd }}\) quadrant
- C \(3^{\text {rd }}\) quadrant
- D \(4^{\text {th }}\) quadrant
Answer & Solution
Correct Answer
(C) \(3^{\text {rd }}\) quadrant
Step-by-step Solution
Detailed explanation
A: \(\sin A B: \(\cos B > 0\) and not in \(1^{\text {st }}\) Q \(\implies\) B in \(4^{\text {th }}\) Q. \(\cos A = -\sqrt{1 - \left(-\frac{24}{25}\right)^2} = -\frac{7}{25}\) \(\sin B = -\sqrt{1 - \left(\frac{15}{17}\right)^2} = -\frac{8}{17}\)…
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