TS EAMCET · Maths · Straight Lines
If \(a \alpha^2+b \beta^2+c \alpha \beta+d=0\) is the transformed equation of \(4 x^2+\sqrt{3} x y+5 y^2-4=0\) obtained by using \(\alpha=\frac{\sqrt{3}}{2} x+\frac{y}{2}\) and \(\beta=-\frac{x}{2}+\frac{\sqrt{3}}{2} y\), then \(c(a+b+d)=\)
- A 0
- B \(13 \sqrt{3}\)
- C \(5 \sqrt{3}\)
- D 6
Answer & Solution
Correct Answer
(C) \(5 \sqrt{3}\)
Step-by-step Solution
Detailed explanation
\(a \alpha^2+b \beta^2+c \alpha \beta+d=0\) is the transformed equation of \(4 x^2+\sqrt{3} x y+5 y^2-4=0\) where, \(\begin{aligned} & \alpha=\frac{\sqrt{3}}{2} x+\frac{y}{2} \\ & \beta=\frac{-x}{2}+\frac{\sqrt{3} y}{2} \end{aligned}\) From Eqs. (i) and (ii), we get…
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