TS EAMCET · Maths · Circle
If \((1,1),(-2,2),(2,-2)\) are 3 points on a circle \(S\), then the perpendicular distance from the centre of the circle \(S\) to the line \(3 x-4 y+1=0\) is
- A \(\frac{1}{2}\)
- B 1
- C \(\frac{23}{10}\)
- D 2
Answer & Solution
Correct Answer
(A) \(\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
Let \(A \equiv(1,1), B \equiv(-2,2), C \equiv(2,-2)\) Slope of \(A B=\frac{-1}{3}\) Slope of \(A C=\frac{-2-1}{2-1}=-3\) Mid point of \(A B=\left(\frac{-1}{2}, \frac{3}{2}\right)\) Mid point of \(A C=\left(\frac{3}{2}, \frac{-1}{2}\right)\) Equation of \(\perp\) bisector of…
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