TS EAMCET · Maths · Indefinite Integration
\(\frac{d}{d x}\left[a \tan ^{-1} x+b \log \left(\frac{x-1}{x+1}\right)\right]=\frac{1}{x^4-1}\) \(\Rightarrow a-2 b\) is equal to
- A 1
- B -1
- C 0
- D 2
Answer & Solution
Correct Answer
(B) -1
Step-by-step Solution
Detailed explanation
Given, \(\frac{d}{d x}\left[a \tan ^{-1} x+b \log \left(\frac{x-1}{x+1}\right)\right]=\frac{1}{x^4-1}\) On integrating both sides, we get…
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