TS EAMCET · Maths · Definite Integration
Assertion \(\int_{-a}^a f(x) d x=\int_0^a(f(x)+f(-x)) d x\) Reason (R) \(\int_a^b f(x) d x=\int_{g(a)}^{g(b)} f(g(u)) g^{\prime}(u) d u\) The correct option among the following is
- A (A) is true, \((R)\) is true and \((R)\) is the correct explanation for (A)
- B \((A)\) is true, \((R)\) is true but \((R)\) is not the correct explanation for \((A)\)
- C \((A)\) is true but \((R)\) is false
- D (A) is false but (R) is true
Answer & Solution
Correct Answer
(C) \((A)\) is true but \((R)\) is false
Step-by-step Solution
Detailed explanation
We have, \(A=\int_{-a}^a f(x) d x=\int_0^a(f(x)+f(-x)) d x\) A is true, \(\quad R=\int_a^b f(x) d x=\int_{g(a)}^{g(b)} f\left(g(u) g^{\prime}(u) d u\right.\) Put, \(x=g(u), d x=g(u) d u\) at \(x=a=g(u)\) and \(x=b \quad u=g^{-1}(b) \Rightarrow u=g^{-1}(a)\)…
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