TS EAMCET · Maths · Matrices
\(\operatorname{adj}\left[\begin{array}{ccc}1 & 0 & 2 \\ -1 & 1 & -2 \\ 0 & 2 & 1\end{array}\right]=\left[\begin{array}{ccc}5 & a & -2 \\ 1 & 1 & 0 \\ -2 & -2 & b\end{array}\right], \quad\) then \(\left[\begin{array}{ll}a & b\end{array}\right]\) is equal to
- A [− 4 1]
- B [− 4 −1]
- C [4 1]
- D [4 −1]
Answer & Solution
Correct Answer
(C) [4 1]
Step-by-step Solution
Detailed explanation
Given that adj \(\left[\begin{array}{ccc}1 & 0 & 2 \\ -1 & 1 & -2 \\ 0 & 2 & 1\end{array}\right]=\left[\begin{array}{ccc}5 & a & -2 \\ 1 & 1 & 0 \\ -2 & -2 & b\end{array}\right]\qquad\ldots\text{(i)}\)…
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