TS EAMCET · Maths · Three Dimensional Geometry
A unit vector \(e=a \hat{i}+b \hat{j}+c k\) is coplanar with the vectors \(\hat{i}-3 \hat{j}+5 \hat{k}\) and \(3 \hat{i}+\hat{j}-5 \hat{k}\). If \(\vec{e}\) is perpendicular to the vector \(\hat{i}+\hat{j}+\hat{k}\) then \(2 a^2+3 b^2+4 c^2=\)
- A \(1\)
- B \(3\)
- C \(-1\)
- D \(\sqrt{2}\)
Answer & Solution
Correct Answer
(B) \(3\)
Step-by-step Solution
Detailed explanation
\(\vec{e}\) is coplanar with \(\hat{i}-3 \hat{j}+5 \hat{k}\) and \(3 \hat{i}+\hat{j}-5 \hat{k}\) \(\left|\begin{array}{ccc}a & b & c \\ 1 & -3 & 5 \\ 3 & 1 & -5\end{array}\right|=0 \Rightarrow a+2 b+c=0\) ...(i)…
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