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TS EAMCET · Maths · Circle

A rhombus is inscribed in the region common to the two circles \(x^2+y^2-4 x-12=0\) and \(x^2+y^2+4 x-12=0\). If the line joining the centres of these circles and the common chord of them are the diagonals of this rhombus, then the area (in Sq. units) of the rhombus is

  1. A \(16 \sqrt{3}\)
  2. B \(4 \sqrt{3}\)
  3. C \(12 \sqrt{3}\)
  4. D \(8 \sqrt{3}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(8 \sqrt{3}\)

Step-by-step Solution

Detailed explanation

The circles have centers \((2,0)\) and \((-2,0)\) and radius is 4 \(\therefore y\)-axis is their common chord. \(\triangle \mathrm{ABC}\) is equilateral \(\Delta\). Hence, area of \(A D B C=\frac{2 \times \sqrt{3}}{4}(4)^2=8 \sqrt{3}\)