TS EAMCET · Maths · Circle
A circle \(S\) passes through the points of intersection of the circles \(x^2+y^2-2 x-3=0\) and \(x^2+y^2-2 y=0\). If \(x+y+1=0\) is a tangent to the circle \(S\), then equation of \(S\) is
- A \(2 x^2+2 y^2+2 x+2 y+3=0\)
- B \(2 x^2+2 y^2-2 x-2 y+3=0\)
- C \(x^2+y^2-2 x-2 y+3=0\)
- D \(2 x^2+2 y^2-2 x-2 y-3=0\)
Answer & Solution
Correct Answer
(D) \(2 x^2+2 y^2-2 x-2 y-3=0\)
Step-by-step Solution
Detailed explanation
Required circle is…
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