TS EAMCET · Chemistry · Classification of Elements and Periodicity in Properties
Which of the following sequence is correct for decreasing order of ionic radius?
- A \(\mathrm{I}^{-}>\mathrm{Se}^{2-}>\mathrm{Br}^{-}>\mathrm{O}^{2-}>\mathrm{F}^{-}\)
- B \(\mathrm{Se}^{2-}>\mathrm{I}^{-}>\mathrm{Br}^{-}>\mathrm{F}^{-}>\mathrm{O}^{2-}\)
- C \(\mathrm{I}^{-}>\mathrm{Se}^{2-}>\mathrm{O}^{2-}>\mathrm{Br}^{-}>\mathrm{F}^{-}\)
- D \(\mathrm{Se}^{2-}>\mathrm{I}^{-}>\mathrm{Br}^{-}>\mathrm{O}^{2-}>\mathrm{F}^{-}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{I}^{-}>\mathrm{Se}^{2-}>\mathrm{Br}^{-}>\mathrm{O}^{2-}>\mathrm{F}^{-}\)
Step-by-step Solution
Detailed explanation
\begin{array}{c|c|c} \mathrm{F}^{-}=9+1=10 & \mathrm{Br}^{-}=35+1=36 & \mathrm{I}^{-}=53+1=54 \\ \mathrm{O}^{2-}=8+2=10 & \mathrm{Se}^{2-}=34+2=36 & \\ \mathrm{O}, \mathrm{F} \Rightarrow \text { Period 2 } & \mathrm{Br}, \mathrm{Se} \Rightarrow \text { Period 4 } & \end{array}…
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