TS EAMCET · Chemistry · Chemical Kinetics
What is the slope of the straight line for the graph drawn between \(\ln k\) and \(\frac{1}{T}\), where \(k\) is the rate constant of a reaction at temperature \(T\) ?
- A \(\frac{-E_a}{2.303 R}\)
- B \(\frac{-E_a}{R}\)
- C \(\frac{E_a}{R}\)
- D \(\frac{R}{E_a}\)
Answer & Solution
Correct Answer
(B) \(\frac{-E_a}{R}\)
Step-by-step Solution
Detailed explanation
Arrhenius equation is \(k=A e^{-E_a / R T}\) On taking log both sides, \(\ln k=\ln A-\frac{E_a}{R T}\) or \(\quad \ln k=-\frac{E_a}{R T}+\ln A\) Since, the reaction, \(y=m x+c\) when a graph is plotted between \(\ln k\) and \(\frac{1}{T}\) a straight line is obtained. The slope…
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