TS EAMCET · Chemistry · Solutions
The solubility product of a sparingly soluble \(A B_2\) salt is \(2.56 \times 10^{-4} \mathrm{M}^3\) at \(25^{\circ} \mathrm{C}\). The \(K_f\) of water is \(1.8 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}\). The depression in freezing point of a standard solution of \(A B_2\) is
- A 0.432 K
- B 0.216 K
- C 0.108 K
- D 13.824 K
Answer & Solution
Correct Answer
(B) 0.216 K
Step-by-step Solution
Detailed explanation
Let, solubility of \(A B_2\) (1:2 type electrolyte) is pure water \(=5 \mathrm{~mol} \mathrm{~L}^{-1}=5 \mathrm{M}\) \(\Rightarrow K_{\mathrm{sp}}=4 S^3=2.56 \times 10^{-4} \mathrm{M}^3\) (given) \(\therefore S=0.04 \mathrm{M}=0.04 \mathrm{~m}\) (molal) under standard condition…
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