TS EAMCET · Chemistry · Structure of Atom
The radius of first Bohr orbit of hydrogen atom is same as that of orbit (n) of hydrogen like species X. (n) and X respectively are
- A (2), \(\mathrm{Li}^{2+}\)
- B (3), \(\mathrm{Li}^{2+}\)
- C (2), \(\mathrm{Be}^{3+}\)
- D (2), \(\mathrm{He}^{+}\)
Answer & Solution
Correct Answer
(C) (2), \(\mathrm{Be}^{3+}\)
Step-by-step Solution
Detailed explanation
Radius of ' \(n{ }^{\text {th' }}\) orbit of a hydrogen-like species is:- \[ r_n=\frac{0.529 n^2}{z} Å \] For first orbit of hydrogen atom, \(r\) \(=0.529 Å\) the radii to be equal; \(\mathrm{n}^2=\mathrm{z}\) \(\Rightarrow \mathrm{n}=2\) for \(\mathrm{Be}^{3+}\) whose…
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